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In a three-phase supply system the two-wattmeter method was used to measure the input power to an inductive load which has a power factor of 0,8. The values indicated on the instruments are 8 kW and 4 kW respectively.   The line voltage is 380 V.

Given:

  • P1 = 8KW
  • P2 = 4KW
  • COS O = 380 V

Calculate the:       

  • Total input power   
  • Line current

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Total input power calculations

PT = P1 + P2.
     = (8+4)KW
     = 12KW

Line current calculations


 

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